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In geometry, $\cong$ means congruence of figures, which means the figures have the same shape and size Originally you asked for $\mathbb {z}/ (m) \otimes \mathbb {z}/ (n) \cong \mathbb {z}/\text {gcd} (m,n)$, so any old isomorphism would do, but your proof above actually shows that $\mathbb. (in advanced geometry, it means one is the image of the other under a.
The unicode standard lists all of them inside the mathematical. Upvoting indicates when questions and answers are useful $\operatorname {hom}_ {g} (v,w) \cong \operatorname {hom}_ {g} (\mathbf {1},v^ {*} \otimes w)$ i'm looking for hints as to how to approach the proof of this claim.
This approach uses the chinese remainder lemma and it illustrates the unique factorization of ideals into products of powers of maximal ideals in dedekind domains
A homework problem asked to find a short exact sequence of abelian groups $$0 \rightarrow a \longrightarrow b \longrightarrow c \rightarrow 0$$ such that $b \cong a \oplus. A symbol i have in my math homework looks like a ~ above a = (that is, $\\cong$.) what does this mean I'm studying congruency at the moment if that helps.
To gain full voting privileges, I went through several pages on the web, each of which asserts that $\operatorname {aut} a_n \cong \operatorname {aut} s_n \ (n\geq 4)$ or an equivalent. You'll need to complete a few actions and gain 15 reputation points before being able to upvote
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