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323k subscribers in the learnmath community I think these claims are rooted in the conjecture that pi is a normal number. this means that the digits are uniformly distributed in any numerical base Questions, no matter how basic…
In base 10, the constant is 0.12345678910111213. $$12345678910111213.$$ find the last two digits of this number when it is divisible by $72$. My main question here is that in order to be simply normal, each digit must be equally likely to appear throughout the entire.
This is an infinite string of digits
But this string, when we try to interpret it in decimals, does not encode a number, i.e., an element of $ {\mathbb n}$ or $ {\mathbb r}$. Basically, the question asks us to find the nth digit in the following sequence $$12345678910111213\\dots9899100101\\dots$$ where the 10th digit is $1$, the 11th digit is. Is the number $0.1234567891011121314\\ldots$ a rational or irrational number
The number has a very clear pattern but however in order for the number to be a rational number it would have to. This is a transcendental number, in fact one of the best known ones, it is $6+$ champernowne's number Kurt mahler was first to show that the number is transcendental, a proof can be found. The number 12345678910111213.979899 consists of all the integers from 1 through 99 written back to back
Is it a multiple of 9
You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful A very large number is formed by writing consecutive digits this way
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